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Posted

I think it's very natural, he is an obvious muscular freak, not even steroids and weights would do that for most people.

 

Like EPO can't turn a donkey into a racehorse?

 

(should I add a hashtag to that?) :ph34r:

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Posted

Jinne Fanie, that made me sad now boet.

I was a massive fan.

 

I want to watch that movie Rush, anyone seen it ?

 

Yup seen it. Quite an eye opener on Niki Lauda and James Hunt. :thumbup:

Posted

Yup seen it. Quite an eye opener on Niki Lauda and James Hunt. :thumbup:

 

Well, if my man Prince says it's good, I am gonna have to go out and get it.

 

Fanie, no worries man, I come from watching the stuff as a youngster in the 70's.

Many drivers I still enjoy from all the era's.

Posted

http://upload.wikimedia.org/math/1/0/a/10a72d433d7433a3ec5689a74ce9b321.png

since 2 is the value for which the unknown quantity in

http://upload.wikimedia.org/math/4/8/3/4837c8153b14f5adad59c921a4a8ce4a.png

is true.

But the expression

http://upload.wikimedia.org/math/8/7/5/875e143444582c6898069268e28faf7c.png

requires a value to be found for the unknown quantity in

http://upload.wikimedia.org/math/5/2/1/521ea81d7eb18ae66267c863d9390af1.png

But any number multiplied by 0 is 0 and so there is no number that solves the equation.

The expression

http://upload.wikimedia.org/math/d/a/7/da7b7ab02ca1a7ae41b8cb4f6975b224.png

requires a value to be found for the unknown quantity in

http://upload.wikimedia.org/math/8/c/4/8c4054f1038b8ff0fc17b70f155b87cc.png

Again, any number multiplied by 0 is 0 and so this time every number solves the equation instead of there being a single number that can be taken as the value of 0/0.

Posted

http://upload.wikimedia.org/math/1/0/a/10a72d433d7433a3ec5689a74ce9b321.png

since 2 is the value for which the unknown quantity in

http://upload.wikimedia.org/math/4/8/3/4837c8153b14f5adad59c921a4a8ce4a.png

is true.

But the expression

http://upload.wikimedia.org/math/8/7/5/875e143444582c6898069268e28faf7c.png

requires a value to be found for the unknown quantity in

http://upload.wikimedia.org/math/5/2/1/521ea81d7eb18ae66267c863d9390af1.png

But any number multiplied by 0 is 0 and so there is no number that solves the equation.

The expression

http://upload.wikimedia.org/math/d/a/7/da7b7ab02ca1a7ae41b8cb4f6975b224.png

requires a value to be found for the unknown quantity in

http://upload.wikimedia.org/math/8/c/4/8c4054f1038b8ff0fc17b70f155b87cc.png

Again, any number multiplied by 0 is 0 and so this time every number solves the equation instead of there being a single number that can be taken as the value of 0/0.

 

http://img4.wikia.nocookie.net/__cb20130614191515/glee/images/4/4b/MyBrainHurts.gifhttp://24.media.tumblr.com/tumblr_m07z2z1gIs1qeh1a7o1_400.gif

Posted

http://img4.wikia.nocookie.net/__cb20130614191515/glee/images/4/4b/MyBrainHurts.gifhttp://24.media.tumblr.com/tumblr_m07z2z1gIs1qeh1a7o1_400.gif

http://upload.wikimedia.org/math/7/3/4/734c1a1e47b46e1029886116e401d3ea.png

http://upload.wikimedia.org/math/0/2/5/02534aaba4bbafbfcf895a5fe8326990.png

The following must be true:

http://upload.wikimedia.org/math/d/2/e/d2e283e91dee2cad966314a84da9f1d5.png

Dividing by zero gives:

http://upload.wikimedia.org/math/4/6/9/469c83d5e0959e4caaceea20df153c53.png

Simplified, yields:

http://upload.wikimedia.org/math/c/4/c/c4c9b852c938da096b69fc257a7a8d82.png

 

I call that "hub logic".

Posted

http://upload.wikimedia.org/math/7/3/4/734c1a1e47b46e1029886116e401d3ea.png

http://upload.wikimedia.org/math/0/2/5/02534aaba4bbafbfcf895a5fe8326990.png

The following must be true:

http://upload.wikimedia.org/math/d/2/e/d2e283e91dee2cad966314a84da9f1d5.png

Dividing by zero gives:

http://upload.wikimedia.org/math/4/6/9/469c83d5e0959e4caaceea20df153c53.png

Simplified, yields:

http://upload.wikimedia.org/math/c/4/c/c4c9b852c938da096b69fc257a7a8d82.png

 

I call that "hub logic".

 

You cannot divide numbers by zero. THe result is always an error. Just like multiplying anything by infinity.

 

Obviously one could try using negitive numbers, but that will turn the entire outcome negative. That is why you use absolute values in such calculations so as to prevent the rise of imaginary numbers.

Posted

You cannot divide numbers by zero. THe result is always an error. Just like multiplying anything by infinity.

 

Obviously one could try using negitive numbers, but that will turn the entire outcome negative. That is why you use absolute values in such calculations so as to prevent the rise of imaginary numbers.

 

Exactly why I called it hub logic. it seems imaginary a lot of the time.

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